怎样把一组数分成两组,使得每组的和为给定的值a,b?

DP:怎样把一组数分成两组,使得每组的和为给定的值a,b?
表示前x个发票,是否有子集组成y的金额。怎样把一组数分成两组,使得每组的和为给定的值a,b?
, v_x是第x个发票的金额。算到 【怎样把一组数分成两组,使得每组的和为给定的值a,b?】 怎样把一组数分成两组,使得每组的和为给定的值a,b?

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谢邀但是这个问题没有简单的解法,这是一个NP问题
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如果不考虑效率(O(n*S)),可以用类似背包的DP,如下(python)def f(v, i, S, memo): if i \u0026gt;= len(v): return 1 if S == 0 else 0 if (i, S) not in memo: # \u0026lt;-- Check if value has not been calculated. count = f(v, i + 1, S, memo) count += f(v, i + 1, S - v, memo) memo = count # \u0026lt;-- Memoize calculated result. return memo # \u0026lt;-- Return memoized value.def g(v, S, memo): subset = for i, x in enumerate(v): # Check if there is still a solution if we include v if f(v, i + 1, S - x, memo) \u0026gt; 0: subset.append(x) S -= x return subsetv = sum = int(input())memo = dict()if f(v, 0, sum, memo) == 0: print("There are no valid subsets.")else: print(g(v, sum, memo))


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